QB132 V2 Quantum Boards × 1 V2 3000K

ChiefRunningPhist

Drunk on Knowledge
I would propose some experimentation. My hypothesis is that you will not be able to measure any difference.
Sure.

I've seemed to notice posts about temps being reduced when doubling board realestate but a true expirement would be good.

Let's use a (5) × 5gal DWC in a 4x4 for thought expirement purposes (and random musings) in the meantime lol. Assuming water level in each at 3gal.

3gal × 5 × 3.79kg/gal
=
56.85kg of water not counting plant weight.

Tent might weigh 10kg. The air is ~3.85kg. So the water seems by far the majority composition of the system. Imagining a closed system within the bounds of the tent, lets say a duration of 24hrs passes after the energy from 600w of lights being run for 12hrs (7.2kWh) is pumped into the tent (closed system) vs 7.2kWh used to power a space heater in a tent. Regardless of whether a space heater was used or an LED light were used, 7.2kWh will finally be distributed evenly throughout the system with the majority being absorbed and stored in the water. But 1 will achieve equilibrium earlier than the other, or 1 will transfer the total energy to the water faster (due to the different forms of energy transfer being utilized).

The Cp of water is ~76 the Cp of air is ~1. This means that even if the ratio of mass were equal in the closed system between air and water, the energy would be more concentrated in the water. Because heat travels from hot to cold, if the same amount of energy were applied to equal masses of air and water, the air would heat up 76× more and transfer to the water to equalize the gradient.

In the tent that we're assuming is a closed system the proportion of air is not equal, it's ~14.7× less prevalent than the water, ontop of the Cp being ~76× less. Pretty much all energy input to the system will be absorbed by the water, but at what rate?

Using air to transfer the energy is much slower than using light. Visible light isn't absorbed by air. Light is instaneously distributed throughout the physical exteriors of the system with which it reacts with. So the instaneous ambient is effected almost soley by the % of power being converted directly to thermal, or the portion of the tech that is acting like a space heater.

If you have a smaller space heater in a room vs a bigger space heater, 1 will heat the air quicker. A space heater transfers its energy to the air more effecient than a light bulb. It's why we use space heaters instead of fluorescent lights.

I'm not sure exactly what the rate of change would be, but thermodynamically speaking 1 will raise ambient quicker than the other. When you throw exhaust rates in the calculation you effectively increase your air mass and volume and circulation rates, and I think a small % of effeciency increase can be noticed pretty drastically when it comes to ambient.

Imagining what (8) QBs run at 600w compared to a 600w HPS would look like. Seems most have to extract the air much more with HPS vs LED, I think most HPS are close to ~45% effeciency, and LED is closer to ~60% effeciency when driven soft. Only ~15% difference but pretty drastic ambient temp differences.

My hypothesis is ~"more than expected," yours seems ~"less than expected," though I think we both agree that thermodynamically there is a difference in transfer rates and methods, which directly relate to subsequent ambient temps. I don't know for certain and would applaud an expirement. Perhaps I'm not correct, and it's not as noticeable as I think. I think I was wrong once if I try to remember back that long ago haha lol jks I'm often wrong but I think I'm modeling this scenario correctly :)

EDIT:
A 5% effeciency difference using 600w is ~1.8kJ/min delta being added to the air. It only takes ~3.85kJ to raise ambient 1°C. If the system is closed then that's 1°C delta every ~2min.

600w × 5% = 30w ; 30J/s
30J/s × 60s/min = 1,800J/min ; 1.8kJ/min
Cp of air = 1kJ/kg·K°
Mass of tent air = 3.85kg
(3.85kJ/K°) / 1.8kJ/min
=
2.13min/K° of tent air
 
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TerpyTyrone

LED Recruiter
I know if I'm running an led @ max current, its gonna be hot.
But your scenario of heat exchange and proportions theoretically sound correct but I'm not the one playing devils advocate. That would be one hell of a comparison.
Even if it was comparatively "powered" lights.
Say 3500k 600 watts @ 75% of max current amd see what is the most efficient based on heat and par output.
Cobs, strips, boards, etc
 

ChiefRunningPhist

Drunk on Knowledge
I know if I'm running an led @ max current, its gonna be hot.
But your scenario of heat exchange and proportions theoretically sound correct but I'm not the one playing devils advocate. That would be one hell of a comparison.
Even if it was comparatively "powered" lights.
Say 3500k 600 watts @ 75% of max current amd see what is the most efficient based on heat and par output.
Cobs, strips, boards, etc
Mid power LED is the most effecient lighting tech. Meaning it will produce the least amount of initial heat per wall watt used.

What's going to effect ambient temps is the temperature of the tech inside the tent. The effeciency of the tech effects how hot it gets. The more energy used to make light the less energy wasted as heat. The less intial heat made will make the air cooler.

Then there's levels of effeciencies within the tech. LED can have varying effeciency with the same μmol/j output if the SPDs are different. Ie 2 LED can both be rated 2.2μmol/j but 1 can run hotter being driven by the same wattage and outputting the same photon count because certain WV are lower energy than others, or require less power to create than other WV.
 

IrocZ

Really Active Member
Thanks Chief for dumbing it down for us...after the thermodynamics lesson, lol

Mid power LED is the most effecient lighting tech. Meaning it will produce the least amount of initial heat per wall watt used.

What's going to effect ambient temps is the temperature of the tech inside the tent. The effeciency of the tech effects how hot it gets. The more energy used to make light the less energy wasted as heat. The less intial heat made will make the air cooler.

Then there's levels of effeciencies within the tech. LED can have varying effeciency with the same μmol/j output if the SPDs are different. Ie 2 LED can both be rated 2.2μmol/j but 1 can run hotter being driven by the same wattage and outputting the same photon count because certain WV are lower energy than others, or require less power to create than other WV.
Well said sir!

You would think an LED lighting company would do this demonstration. Especially because it would encourage their customers to buy more LEDs.
 

shimz

vapest
Sure.

I've seemed to notice posts about temps being reduced when doubling board realestate but a true expirement would be good.

Let's use a (5) × 5gal DWC in a 4x4 for thought expirement purposes (and random musings) in the meantime lol. Assuming water level in each at 3gal.

3gal × 5 × 3.79kg/gal
=
56.85kg of water not counting plant weight.

Tent might weigh 10kg. The air is ~3.85kg. So the water seems by far the majority composition of the system. Imagining a closed system within the bounds of the tent, lets say a duration of 24hrs passes after the energy from 600w of lights being run for 12hrs (7.2kWh) is pumped into the tent (closed system) vs 7.2kWh used to power a space heater in a tent. Regardless of whether a space heater was used or an LED light were used, 7.2kWh will finally be distributed evenly throughout the system with the majority being absorbed and stored in the water. But 1 will achieve equilibrium earlier than the other, or 1 will transfer the total energy to the water faster (due to the different forms of energy transfer being utilized).

The Cp of water is ~76 the Cp of air is ~1. This means that even if the ratio of mass were equal in the closed system between air and water, the energy would be more concentrated in the water. Because heat travels from hot to cold, if the same amount of energy were applied to equal masses of air and water, the air would heat up 76× more and transfer to the water to equalize the gradient.

In the tent that we're assuming is a closed system the proportion of air is not equal, it's ~14.7× less prevalent than the water, ontop of the Cp being ~76× less. Pretty much all energy input to the system will be absorbed by the water, but at what rate?

Using air to transfer the energy is much slower than using light. Visible light isn't absorbed by air. Light is instaneously distributed throughout the physical exteriors of the system with which it reacts with. So the instaneous ambient is effected almost soley by the % of power being converted directly to thermal, or the portion of the tech that is acting like a space heater.

If you have a smaller space heater in a room vs a bigger space heater, 1 will heat the air quicker. A space heater transfers its energy to the air more effecient than a light bulb. It's why we use space heaters instead of fluorescent lights.

I'm not sure exactly what the rate of change would be, but thermodynamically speaking 1 will raise ambient quicker than the other. When you throw exhaust rates in the calculation you effectively increase your air mass and volume and circulation rates, and I think a small % of effeciency increase can be noticed pretty drastically when it comes to ambient.

Imagining what (8) QBs run at 600w compared to a 600w HPS would look like. Seems most have to extract the air much more with HPS vs LED, I think most HPS are close to ~45% effeciency, and LED is closer to ~60% effeciency when driven soft. Only ~15% difference but pretty drastic ambient temp differences.

My hypothesis is ~"more than expected," yours seems ~"less than expected," though I think we both agree that thermodynamically there is a difference in transfer rates and methods, which directly relate to subsequent ambient temps. I don't know for certain and would applaud an expirement. Perhaps I'm not correct, and it's not as noticeable as I think. I think I was wrong once if I try to remember back that long ago haha lol jks I'm often wrong but I think I'm modeling this scenario correctly :)

EDIT:
A 5% effeciency difference using 600w is ~1.8kJ/min delta being added to the air. It only takes ~3.85kJ to raise ambient 1°C. If the system is closed then that's 1°C delta every ~2min.

600w × 5% = 30w ; 30J/s
30J/s × 60s/min = 1,800J/min ; 1.8kJ/min
Cp of air = 1kJ/kg·K°
Mass of tent air = 3.85kg
(3.85kJ/K°) / 1.8kJ/min
=
2.13min/K° of tent air
That was a lot of flagellation to compare a space heater to an LED, eh? I get what you're saying, but the differences here are much smaller. I am interested in comparing 4 strips vs. 8, 4 boards vs. 8.
 

TerpyTyrone

LED Recruiter
That is assuming that the amount of heat gained per watt is equal.
In the case of leds I'm sure its pretty equal sin curve. Buy among the different types I'm sure once u get beyond 75% of max current the amount of heat , per every watt , will raise more suddenly.
Am I wrong? Between 50-75% the degree per watt isn't as drastic as say 75-100%
 

ChiefRunningPhist

Drunk on Knowledge
That was a lot of flagellation to compare a space heater to an LED, eh? I get what you're saying, but the differences here are much smaller. I am interested in comparing 4 strips vs. 8, 4 boards vs. 8.
I think most HPS are close to ~45% effeciency, and LED is closer to ~60% effeciency when driven soft. Only ~15% difference but pretty drastic ambient temp differences.
EDIT:
A 5% effeciency difference using 600w is ~1.8kJ/min delta being added to the air. It only takes ~3.85kJ to raise ambient 1°C. If the system is closed then that's 1°C delta every ~2min.

600w × 5% = 30w ; 30J/s
30J/s × 60s/min = 1,800J/min ; 1.8kJ/min
Cp of air = 1kJ/kg·K°
Mass of tent air = 3.85kg
(3.85kJ/K°) / 1.8kJ/min
=
2.13min/K° of tent air
Ya a space heater is the same thing as the non light producing part of the LED set-up. That's why I'm using that as an example. They meaure the incredible effeciency of LED with pulsed currents and @65mA per chip (most times). As soon as you turn the juice up they drop pretty considerably in effeciency. The question is how much. If there's at least a 5% effeciency difference between double or halved board realestate then I think you'll notice the ambient temps to be significantly different with time, maybe 1-2 degrees C° would be a guesstimate.

I was trying to give some context. I could have just said the smaller % of power you need to convect, the cooler the air.
 
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ChiefRunningPhist

Drunk on Knowledge
@ChiefRunningPhist
A long standing statement that has been regurgitated 100s of times over on RIU is that 600w of any light will create the same heat. Because 1watt is 3.41btu/h

With a simple answer are you saying this is correct or incorrect?
It can give an idea.

Although 1w does equate to 3.41btu/hr, anticipating heat is a closer estimation with some devices than others due to the different forms of energy transfer utilized to distribute the wall watts throughout the room (convection, conduction, radiation), and the rate at which the room extracts heat from the air.

In 2 rooms with good insulation, if given time for the energy to dissipate, the ambients will be the same. But real world temps depend on rates, not absolute qty of energy. We exhaust air at a rate. The room isn't a closed system. So the rate at which it heats matters.

EDIT:
You have to be careful with RIU (just like everywhere), they have some really smart fellers over there but there's a lot of unsubstantiated claims and incorrect advice. Look for cited sources or links. That's just my $0.02. I've been told things that I thought were correct by some of the big whigs over there only to find they had no clue what they were talking about. I'm not a biologist or plant expert, but I know a fair amount of chemistry, physics, electric, thermo, and math so those are the areas I typically comment on. I make mistakes and I'd encourage all my posts to be scrutinized. I only care about perpetuating truth and fact.
It's correct in a closed system, but bottom line is there may be some differences once you factor in heat loss, rates of heating, etc.
Right on.
 
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TerpyTyrone

LED Recruiter
So far the Jack herer is the star of the grow for vigor and size.
I dont hqve much of a sense of smell ,from snorting drugs for many years, but the stench coming out od this tent when I open it is invigorating!
I have the three big photos in back to go next in a couple weeks at least.
They seem to be losing color from,each evenly. I am wondering if i should,up the calmag to a full dose of 5ml per gallon.
I have one nute bucket to keep it easy for the grow bro. In truth the 5 in front were all ran 12/12 from seed behind the nute schedule of the other plants. So they were getting the flowering nutes while,in transition, if that makes sense.
It worked out well by not overfeeding the autos or the plants that were ran about 6 weeks behind them. But I am starting to see it now in the older photos.
Maybe ita time to make a buCket for the late flowering plants with more Epsom and cal mag?0523191629.jpg0523191630_HDR.jpg0523191626.jpg0523191627_HDR.jpg0523191626_HDR.jpg
By no means are these infirmary bound but I see it losing vigor in late flower when shes hungry. Whatcha think? @Opie1
 

Spondylo Grow

Really Active Member
Hey guys, sorry to jack the thread here, but I see some knowledgeable folks here, and was hoping someone wouldn't mind helping me out with a relatable question:

I just picked up a 4pk of the HLG qb120 V2s. Was wondering if I can run them in series with a driver that I already had, HLG-320H-C1400A. If I turn that driver down so not to max out the boards, would it work? Or do I need to pick up a different driver? Any help or input would be appreciated.
 

TerpyTyrone

LED Recruiter
Glad to help put afellow quantum whore!!!! Welcome to the fam, paradise!!
 

Spondylo Grow

Really Active Member
I can't seem to find an actual spec sheet for those boards to see what they'd run at. But yes you could use that driver.
Do you have a link or the spec sheet you could post?
Glad to help put afellow quantum whore!!!! Welcome to the fam, paradise!!
Thanks guys. I only have the info that is in that link that Terpy posted. I see they recommend the 240H-2100, Giving around 47w per board. Looks like the one I have would run them at only 31w per board, but would still work? Is that right?
 

ChiefRunningPhist

Drunk on Knowledge
Short answer, yes. Can blast full power.



8 x 15...
USER_SCOPED_TEMP_DATA_orca-image--732646572.jpeg_1560350662359.jpeg

Looks like ~21V - 22V forward voltage...
Screenshot_2019-06-12-08-39-43~2.png

LM301B only goes to ~2.88V...
CRF_Fv_Graphs_1.0.png
Trial and error, I'll guess 2.8V and see where that goes..
22V ÷ 2.8V = 7.85 chips; which is pretty close to 8, so it looks like 8 in series, 15 in parallel. 1400mA split 15 ways is ~93mA, and the LM301b is rated 180mA+. Looking at the driver you can see the 320h 1400 has a voltage range of 114 - 229VDC. 4 QB120s in a row at 22V each is 88V and well under the max rating of the 320h 1400.
Screenshot_2019-06-12-08-47-45.png

EDIT:
Ya, 31W is what I calculate too.

Also I guess could have just looked at the chart they provide lol that would have been easier but I like making little pictures and stuff if you haven't noticed lol
 
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